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JEE Main 2026 (23 Jan, Shift 1) · YDSE: Fringe Width & Fringe Positions

YDSE: Fringe Width & Fringe Positions question from JEE Main 2026 (23 Jan, Shift 1)

Q1JEE Main 2026 · 23 JAN · SHIFT 1Easy

YDSE: Fringe Width & Fringe Positions

In two separate Young's double-slit experimental set-ups and two monochromatic light sources of different wavelengths are used to get fringes of equal width. The ratios of the slits separations and that of the wavelengths of light used are 2:12 : 1 and 1:21 : 2 respectively. The corresponding ratio of the distances between the slits and the respective screens ( D1/D2D_1/D_2) is ______。

Numerical answer type. Work it out, then open the answer.

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Answer: 4

  1. Equal fringe width: λ1D1d1=λ2D2d2\frac{\lambda_1D_1}{d_1} = \frac{\lambda_2D_2}{d_2}
  2. D1D2=d1d2⋅λ2λ1=2×2\frac{D_1}{D_2} = \frac{d_1}{d_2}\cdot\frac{\lambda_2}{\lambda_1} = 2\times 2
  3. So D1D2=4\frac{D_1}{D_2} = 4.
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