In U.C.M., when time interval δ t → 0, the angle between change in velocity ( δ v) and linear velocity (v) will be (a) 0° (b) 90° (c) 180° (d) 45°

Answer: (b). As δ t → 0, δ v points towards the centre (it gives the centripetal acceleration). The velocity is along the tangent, which is perpendicular to the radius. So the answer is (b) 90°.

In U.C.M., when time interval δ t → 0, the angle between change in… | MHT CET 2019 (2 May, Shift 2)

Q35MHT CET 2019 · 2 MAY · SHIFT 2Medium

Angular Variables

In U.C.M., when time interval $\delta t \to 0$ , the angle between change in velocity ( $\delta \vec{v}$ ) and linear velocity $(\vec{v})$ will be

Show answer and solution

Answer: (b)

As $\delta t \to 0$ , $\delta \vec v$ points towards the centre (it gives the centripetal acceleration).
The velocity is along the tangent, which is perpendicular to the radius.
So the answer is (b) $90^\circ$ .

Report a mistake

Angular Variables question from MHT CET 2019 (2 May, Shift 2)

More questions on Angular Variables