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JEE Main 2022 (29 Jun, Shift 1) · Applications of Dimensional Analysis

Applications of Dimensional Analysis question from JEE Main 2022 (29 Jun, Shift 1)

Q34JEE Main 2022 · 29 JUN · SHIFT 1Easy

Applications of Dimensional Analysis

In van der Waal equation [P+aV2]\left[P + \frac{a}{V^2}\right] [V −- b] = RT; P is pressure, V is volume, R is universal gas constant and T is temperature. The ratio of constants ab\frac{a}{b} is dimensionally equal to:

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Answer: (c)

  1. [a]=[P][V2][a] = [P][V^2] and [b]=[V][b] = [V].
  2. [a/b]=[P][V][a/b] = [P][V].
  3. So the answer is (c) PVPV.
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