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MHT CET 2019 (3 May, Shift 1) · YDSE: Film, Medium & Two Wavelengths

YDSE: Film, Medium & Two Wavelengths question from MHT CET 2019 (3 May, Shift 1)

Q60MHT CET 2019 · 3 MAY · SHIFT 1Medium

YDSE: Film, Medium & Two Wavelengths

In Young's double slit experiment fifth dark fringe is formed opposite to one of the slits. D is the distance between the slits and the screen and $d$ is the separation between the slits, then the wavelength of light used is

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Answer: (b)

Path difference in front of a slit $= \dfrac{d^2}{2D}$ .
Fifth dark: $\dfrac{d^2}{2D} = \dfrac{9\lambda}{2} \Rightarrow \lambda = \dfrac{d^2}{9D}$
So the answer is (b) $\frac{d^2}{9D}$ .

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