In Young's double slit experiment, for the n th dark fringe ( n = 1, 2, 3,) the phase difference of the interfering waves in radian will be (a) n · π/2 (b) (2n+1)π (c) (2n-1)π (d) (2n-1)π/2

Answer: (c). Dark fringe: phase difference is an odd multiple of π: π, 3π, 5π, For n = 1, 2, 3, this is φ = (2n-1)π. So the answer is (c) (2n-1)π.

In Young's double slit experiment, for the n th dark fringe ( n = 1… | MHT CET 2026 (19 Apr, Shift 1)

Q3MHT CET 2026 · 19 APR · SHIFT 1Easy

Superposition, Coherence & Intensity

In Young's double slit experiment, for the $n$ th dark fringe ( $n = 1, 2, 3, \ldots$ ) the phase difference of the interfering waves in radian will be

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Answer: (c)

Dark fringe: phase difference is an odd multiple of $\pi$ : $\pi, 3\pi, 5\pi, \ldots$
For $n = 1, 2, 3, \ldots$ this is $\phi = (2n-1)\pi$ .
So the answer is (c) $(2n-1)\pi$ .

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