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MHT CET 2024 (3 May, Shift 2) · YDSE: Film, Medium & Two Wavelengths

YDSE: Film, Medium & Two Wavelengths question from MHT CET 2024 (3 May, Shift 2)

Q37MHT CET 2024 · 3 MAY · SHIFT 2Medium

YDSE: Film, Medium & Two Wavelengths

In Young's double slit experiment, in an interference pattern, second minimum is observed exactly in front of one slit. The distance between the two coherent sources is ' $d$ ' and the distance between the source and screen is ' $D$ '. The wave length of light $(\lambda)$ used is

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Answer: (c)

Path difference in front of a slit $= \dfrac{d^2}{2D}$ .
Second minimum: $\dfrac{d^2}{2D} = \dfrac{3\lambda}{2} \Rightarrow \lambda = \dfrac{d^2}{3D}$
So the answer is (c) $\frac{d^2}{3D}$ .

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