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JEE Main 2024 (29 Jan, Shift 2) · Superposition, Coherence & Intensity

Superposition, Coherence & Intensity question from JEE Main 2024 (29 Jan, Shift 2)

Q51JEE Main 2024 · 29 JAN · SHIFT 2Medium

Superposition, Coherence & Intensity

In Young's double slit experiment, light from two identical sources are superimposing on a screen. The path difference between the two lights reaching at a point on the screen is 7λ/47\lambda/4. The ratio of intensity of fringe at this point with respect to the maximum intensity of the fringe is:

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Answer: (a)

  1. ϕ=2πλ⋅7λ4=7π2\phi = \dfrac{2\pi}{\lambda}\cdot\dfrac{7\lambda}{4} = \dfrac{7\pi}{2}
  2. IImax=cos⁡27π4=(12)2=12\dfrac{I}{I_{max}} = \cos^2\dfrac{7\pi}{4} = \left(\dfrac{1}{\sqrt{2}}\right)^2 = \dfrac{1}{2}
  3. So the answer is (a) 12\dfrac{1}{2}.
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