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MHT CET 2021 (22 Sep, Shift 1) · YDSE: Fringe Width & Fringe Positions

YDSE: Fringe Width & Fringe Positions question from MHT CET 2021 (22 Sep, Shift 1)

Q49MHT CET 2021 · 22 SEP · SHIFT 1Easy

YDSE: Fringe Width & Fringe Positions

In Young's double slit experiment, the $10$ th maximum of wavelength ' $\lambda_1$ ' is at a distance of ' $Y_1$ ' from the central maximum. When the wavelength of the source is changed to ' $\lambda_2$ ', $5^{th}$ maximum is at a distance ' $Y_2$ ' from the central maximum. The ratio $\frac{Y_1}{Y_2}$ is

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Answer: (a)

Bright fringe: $y_n = \frac{n\lambda D}{d}$
$Y_1 = \frac{10\lambda_1 D}{d}$ , $Y_2 = \frac{5\lambda_2 D}{d}$
$\frac{Y_1}{Y_2} = \frac{10\lambda_1}{5\lambda_2} = \frac{2\lambda_1}{\lambda_2}$
So the answer is (a) $\frac{2\lambda_1}{\lambda_2}$ .

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