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YDSE: Fringe Width & Fringe Positions question from NEET 2013

Q71NEET 2013Easy

YDSE: Fringe Width & Fringe Positions

In Young's double slit experiment the distance between the slits and the screen is doubled. The separation between the slits is reduced to half. As a result the fringe width

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Answer: (b)

  1. β=λDd\beta = \frac{\lambda D}{d}
  2. β′=λ(2D)d/2=4β\beta' = \frac{\lambda (2D)}{d/2} = 4\beta
  3. So the answer is (b) four times.
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