In Young's double slit experiment, the fifth maximum with wavelength ' λ₁ ' is at a distance ' y₁ ' and the same maximum with wavelength ' λ₂ ' is at a distance ' y₂ ' measured from the central bright band. Then (y₁)/(y₂) is equal to [D and d are constant] (a) (λ₁)/(λ₂) (b) (λ₂)/(λ₁) (c) (λ₁²)/(λ₂²) (d) (λ₂²)/(λ₁²)

Answer: (a). y₅ = (5λ D)/(d) ∝ λ for fixed D, d (y₁)/(y₂) = (λ₁)/(λ₂), so the answer is (a).

In Young's double slit experiment, the fifth maximum with wavelength… | MHT CET 2023 (11 May, Shift 2)

Q33MHT CET 2023 · 11 MAY · SHIFT 2Easy

YDSE: Fringe Width & Fringe Positions

In Young's double slit experiment, the fifth maximum with wavelength ' $\lambda_1$ ' is at a distance ' $y_1$ ' and the same maximum with wavelength ' $\lambda_2$ ' is at a distance ' $y_2$ ' measured from the central bright band. Then $\frac{y_1}{y_2}$ is equal to [D and $d$ are constant]

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Answer: (a)

$y_5 = \frac{5\lambda D}{d} \propto \lambda$ for fixed $D$ , $d$
$\frac{y_1}{y_2} = \frac{\lambda_1}{\lambda_2}$ , so the answer is (a).

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YDSE: Fringe Width & Fringe Positions question from MHT CET 2023 (11 May, Shift 2)

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