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MHT CET 2024 (10 May, Shift 1) · YDSE: Fringe Width & Fringe Positions

YDSE: Fringe Width & Fringe Positions question from MHT CET 2024 (10 May, Shift 1)

Q23MHT CET 2024 · 10 MAY · SHIFT 1Easy

YDSE: Fringe Width & Fringe Positions

In young's double slit experiment, the nnth maximum of wavelength λ1\lambda_1 is at a distance of y1y_1 from the central maximum. When the wavelength of the source is changed to λ2,(n3)\lambda_2, \left(\frac{n}{3}\right)th maximum is at a distance of y2y_2 from its central maximum. The ratio y1y2\frac{y_1}{y_2} is

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Answer: (a)

  1. y=nλDdy = \frac{n\lambda D}{d}
  2. y1=nλ1Ddy_1 = \frac{n\lambda_1D}{d}, y2=n3⋅λ2Ddy_2 = \frac{n}{3}\cdot\frac{\lambda_2D}{d}
  3. y1y2=3λ1λ2\frac{y_1}{y_2} = \frac{3\lambda_1}{\lambda_2}, so the answer is (a).
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