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MHT CET 2026 (19 May, Shift 2) · YDSE: Fringe Width & Fringe Positions

YDSE: Fringe Width & Fringe Positions question from MHT CET 2026 (19 May, Shift 2)

Q2MHT CET 2026 · 19 MAY · SHIFT 2Easy

YDSE: Fringe Width & Fringe Positions

In Young's double slit experiment, the separation between the slits is decreased to $\left(\frac{1}{3}\right)^{th}$ of its original distance and the distance between the slits and the screen is doubled. The fringe width

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Answer: (d)

$\beta = \frac{\lambda D}{d}$
$\beta' = \frac{\lambda (2D)}{d/3} = 6\frac{\lambda D}{d} = 6\beta$
So the answer is (d) 6 times.

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