In Young’s double slit experiment the separation d between the slits… | NEET 2018

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YDSE: Fringe Width & Fringe Positions

In Young’s double slit experiment the separation d between the slits is 2 mm, the wavelength $\lambda$ of the light used is 5896 $\text{\AA}$ and distance D between the screen and slits is 100 cm. It is found that the angular width of the fringes is 0.20°. To increase the fringe angular width to 0.21° (with same $\lambda$ and D) the separation between the slits needs to be changed to

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Answer: (a)

Angular width $\theta = \frac{\lambda}{d}$ , so $\theta \propto \frac{1}{d}$ .
$d' = d\frac{\theta}{\theta'} = 2\times\frac{0.20}{0.21} = 1.9$ mm
So the answer is (a) 1.9 mm.

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