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MHT CET 2024 (9 May, Shift 2) · Superposition, Coherence & Intensity

Superposition, Coherence & Intensity question from MHT CET 2024 (9 May, Shift 2)

Q49MHT CET 2024 · 9 MAY · SHIFT 2Medium

Superposition, Coherence & Intensity

In Young's double slit experiment using monochromatic light of wavelength ' λ\lambda ', the maximum intensity of light at a point on the screen is ' K ' units. The intensity of light at a point where the path difference is λ6\frac{\lambda}{6} is (cos⁡60∘=sin⁡30∘=0.5,sin⁡60∘=cos⁡30∘=3/2)\left(\cos 60^\circ = \sin 30^\circ = 0.5, \sin 60^\circ = \cos 30^\circ = \sqrt{3}/2\right)

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Answer: (a)

  1. Δx=λ/6⇒ϕ=π/3\Delta x = \lambda/6 \Rightarrow \phi = \pi/3.
  2. I=Kcos⁡230∘=3K4I = K\cos^2 30^\circ = \dfrac{3K}{4}
  3. So the answer is (a) 3K4\dfrac{3K}{4}.
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