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JEE Main 2023 (25 Jan, Shift 1) · YDSE: Fringe Width & Fringe Positions

YDSE: Fringe Width & Fringe Positions question from JEE Main 2023 (25 Jan, Shift 1)

Q35JEE Main 2023 · 25 JAN · SHIFT 1Easy

YDSE: Fringe Width & Fringe Positions

In Young's double slits experiment, the position of 5th^{\text{th}} bright fringe from the central maximum is 5 cm. The distance between slits and screen is 1 m and wavelength of used monochromatic light is 600 nm. The separation between the slits is:

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Answer: (a)

  1. Bright fringe: y5=5λDd⇒d=5λDy5y_5 = \frac{5\lambda D}{d} \Rightarrow d = \frac{5\lambda D}{y_5}
  2. d=5×600×10−9×10.05=6×10−5 md = \frac{5 \times 600\times10^{-9} \times 1}{0.05} = 6\times10^{-5}\text{ m}
  3. So the answer is (a) 60 μ60\ \mum.
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