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MHT CET 2026 (17 Apr, Shift 2) · Superposition, Coherence & Intensity

Superposition, Coherence & Intensity question from MHT CET 2026 (17 Apr, Shift 2)

Q4MHT CET 2026 · 17 APR · SHIFT 2Easy

Superposition, Coherence & Intensity

In Young's experiment, the intensity ratio of the maxima and minima in an interference pattern produced by two coherent sources is $36 : 1$ . The ratio of the amplitudes of the two individual sources will be

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Answer: (c)

$\frac{I_{max}}{I_{min}} = \left(\frac{a_1+a_2}{a_1-a_2}\right)^2 = 36$
$\frac{a_1+a_2}{a_1-a_2} = 6 \Rightarrow a_1 + a_2 = 6a_1 - 6a_2 \Rightarrow 5a_1 = 7a_2$
$\frac{a_1}{a_2} = \frac{7}{5}$
So the answer is (c) $7 : 5$ .

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