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JEE Main 2002 (AIEEE) · Angular Momentum & its Conservation

Angular Momentum & its Conservation question from JEE Main 2002 (AIEEE)

Q96JEE Main 2002 · AIEEEMedium

Angular Momentum & its Conservation

Initial angular velocity of a circular disc of mass MM is ω1.\omega_1. Then two small spheres of mass mm are attached gently to diametrically opposite points on the edge of the disc. What is the final angular velocity of the disc?

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Answer: (c)

  1. Disc: I1=12MR2I_1 = \frac{1}{2}MR^2; two spheres on the edge add 2mR22mR^2.
  2. Conservation of LL: 12MR2ω1=(12M+2m)R2ω2\frac{1}{2}MR^2\omega_1 = \left(\frac{1}{2}M + 2m\right)R^2\omega_2.
  3. ω2=MM+4mω1\omega_2 = \frac{M}{M+4m}\omega_1
  4. So the answer is (c) (MM+4m)ω1\left(\frac{M}{M+4m}\right)\omega_1.
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