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MHT CET 2025 (21 Apr, Shift 1) · Motional EMF

Motional EMF question from MHT CET 2025 (21 Apr, Shift 1)

Q12MHT CET 2025 · 21 APR · SHIFT 1Medium

Motional EMF

Initially a rectangular coil with length vertical is moving out with constant velocity ' vv ' in a constant magnetic field ' BB ' towards right. Now the same coil is rotated through 90∘90^\circ in same plane in same magnetic field B and the coil is moving with same velocity v\mathbf{v}. The magnitude of induced e.m.f. is now

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Answer: (a)

  1. Emf of a coil leaving the field: ε=Bℓv\varepsilon = B\ell v, where ℓ\ell is the side perpendicular to v⃗\vec v (the vertical side here).
  2. Initially the length ll (longer side) is vertical: ε1=Blv\varepsilon_1 = Blv.
  3. After rotating by 90∘90^\circ the breadth bb (shorter side) is vertical: ε2=Bbv\varepsilon_2 = Bbv.
  4. Since b<lb < l, ε2<ε1\varepsilon_2 < \varepsilon_1. So the working gives (b) less than the initial emf.
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