Interference fringes are observed on a screen by illuminating two… | JEE Main 2020 (2 Sep, Shift 1)

Q65JEE Main 2020 · 2 SEP · SHIFT 1Medium

YDSE: Fringe Width & Fringe Positions

Interference fringes are observed on a screen by illuminating two thin slits 1 mm apart with a light source ( $\lambda$ = 632.8 nm). The distance between the screen and the slits is 100 cm. If a bright fringe is observed on a screen at a distance of 1.27 mm from the central bright fringe, then the path difference between the waves, which are reaching this point from the slits is close is

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Answer: (a)

Path difference $\Delta x = \frac{y d}{D}$
$\Delta x = \frac{1.27\times10^{-3} \times 1\times10^{-3}}{1} = 1.27\times10^{-6}\text{ m}$ (about $2\lambda$ , so it is a bright fringe)
So the answer is (a) $1.27\ \mu$ m.

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