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JEE Main 2024 (6 Apr, Shift 1) · Electric Flux & Gauss's Law

Electric Flux & Gauss's Law question from JEE Main 2024 (6 Apr, Shift 1)

Q47JEE Main 2024 · 6 APR · SHIFT 1Easy

Electric Flux & Gauss's Law

$\sigma$ is the uniform surface charge density of a thin spherical shell of radius R. The electric field at any point on the surface of the spherical shell is:

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Answer: (b)

Total charge $Q = \sigma \cdot 4\pi R^2$ .
At the surface $E = \dfrac{Q}{4\pi\epsilon_0 R^2} = \dfrac{\sigma \cdot 4\pi R^2}{4\pi\epsilon_0 R^2} = \dfrac{\sigma}{\epsilon_0}$
So the answer is (b).

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