[L²M¹T⁻²] are the dimensions of (a) torque (b) force (c) angular acceleration (d) angular momentum

Answer: (a). Torque = rF → [L][MLT⁻²] = [ML²T⁻²] Force is [MLT⁻²], angular acceleration [T⁻²], angular momentum [ML²T⁻¹]. So the answer is (a) torque.

[L²M¹T⁻²] are the dimensions of | MHT CET 2019 (3 May, Shift 1)

Q77MHT CET 2019 · 3 MAY · SHIFT 1Easy

Units & Dimensions

$\left[\mathrm{L^{2}M^{1}T^{-2}}\right]$ are the dimensions of

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Answer: (a)

Torque $= rF \to [\mathrm{L}][\mathrm{MLT^{-2}}] = [\mathrm{ML^2T^{-2}}]$
Force is $[\mathrm{MLT^{-2}}]$ , angular acceleration $[\mathrm{T^{-2}}]$ , angular momentum $[\mathrm{ML^2T^{-1}}]$ .
So the answer is (a) torque.

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