Let γ₁ be the ratio of molar specific heat at constant pressure and molar specific heat at constant volume of a monoatomic gas and γ₂ be the similar ratio of diatomic gas. Considering the diatomic gas molecule as a rigid rotator, the ratio, (γ₁)/(γ₂) is: (a) 35/27 (b) 25/21 (c) 21/25 (d) 27/35

Answer: (b). Monoatomic: γ₁ = 5/3; rigid diatomic: γ₂ = 7/5. (γ₁)/(γ₂) = 5/3×5/7 = 25/21 So the answer is (b) 25/21.

Let γ₁ be the ratio of molar specific heat at constant pressure and… | JEE Main 2023 (24 Jan, Shift 2)

Q30JEE Main 2023 · 24 JAN · SHIFT 2Medium

Specific Heats of Gases - Cp, Cv, γ & Mayer's Relation

Let $\gamma_1$ be the ratio of molar specific heat at constant pressure and molar specific heat at constant volume of a monoatomic gas and $\gamma_2$ be the similar ratio of diatomic gas. Considering the diatomic gas molecule as a rigid rotator, the ratio, $\frac{\gamma_1}{\gamma_2}$ is:

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Answer: (b)

Monoatomic: $\gamma_1 = \dfrac{5}{3}$ ; rigid diatomic: $\gamma_2 = \dfrac{7}{5}$ .
$\dfrac{\gamma_1}{\gamma_2} = \dfrac{5}{3}\times\dfrac{5}{7} = \dfrac{25}{21}$
So the answer is (b) $25/21$ .

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Specific Heats of Gases - Cp, Cv, γ & Mayer's Relation question from JEE Main 2023 (24 Jan, Shift 2)

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