Let γ₁ be the ratio of molar specific heat at constant pressure and molar specific heat at constant volume of a monoatomic gas and γ₂ be the similar ratio of diatomic gas. Considering the diatomic gas molecule as a rigid rotator, the ratio (γ₂)/(γ₁) is (a) 37/21 (b) 27/35 (c) 21/25 (d) 35/27

Answer: (c). Monoatomic: γ₁ = 5/3; rigid diatomic: γ₂ = 7/5. (γ₂)/(γ₁) = 7/5×3/5 = 21/25 So the answer is (c) 21/25.

Let γ₁ be the ratio of molar specific heat at constant pressure and… | MHT CET 2023 (12 May, Shift 1)

Q28MHT CET 2023 · 12 MAY · SHIFT 1Medium

Specific Heats of Gases - Cp, Cv, γ & Mayer's Relation

Let $\gamma_1$ be the ratio of molar specific heat at constant pressure and molar specific heat at constant volume of a monoatomic gas and $\gamma_2$ be the similar ratio of diatomic gas. Considering the diatomic gas molecule as a rigid rotator, the ratio $\frac{\gamma_2}{\gamma_1}$ is

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Answer: (c)

Monoatomic: $\gamma_1 = \dfrac{5}{3}$ ; rigid diatomic: $\gamma_2 = \dfrac{7}{5}$ .
$\dfrac{\gamma_2}{\gamma_1} = \dfrac{7}{5}\times\dfrac{3}{5} = \dfrac{21}{25}$
So the answer is (c) $21/25$ .

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Specific Heats of Gases - Cp, Cv, γ & Mayer's Relation question from MHT CET 2023 (12 May, Shift 1)

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