Let γ₁ be the ratio of molar specific heat at constant pressure and molar specific heat at constant volume of a mono-atomic gas and γ₂ be the similar ratio of diatomic gas. Considering the diatomic gas molecule as a rigid rotator, the ratio, γ₁/γ₂ is (a) 27/35 (b) 35/27 (c) 25/21 (d) 21/25

Answer: (c). Monoatomic: γ₁ = 5/3; rigid diatomic: γ₂ = 7/5. (γ₁)/(γ₂) = 5/3×5/7 = 25/21 So the answer is (c) 25/21.

Let γ₁ be the ratio of molar specific heat at constant pressure and… | MHT CET 2026 (13 Apr, Shift 2)

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Specific Heats of Gases - Cp, Cv, γ & Mayer's Relation

Let $\gamma_1$ be the ratio of molar specific heat at constant pressure and molar specific heat at constant volume of a mono-atomic gas and $\gamma_2$ be the similar ratio of diatomic gas. Considering the diatomic gas molecule as a rigid rotator, the ratio, $\gamma_1/\gamma_2$ is

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Answer: (c)

Monoatomic: $\gamma_1 = \dfrac{5}{3}$ ; rigid diatomic: $\gamma_2 = \dfrac{7}{5}$ .
$\dfrac{\gamma_1}{\gamma_2} = \dfrac{5}{3}\times\dfrac{5}{7} = \dfrac{25}{21}$
So the answer is (c) $25/21$ .

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Specific Heats of Gases - Cp, Cv, γ & Mayer's Relation question from MHT CET 2026 (13 Apr, Shift 2)

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