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JEE Main 2023 (1 Feb, Shift 1) · Electric Flux & Gauss's Law

Electric Flux & Gauss's Law question from JEE Main 2023 (1 Feb, Shift 1)

Q62JEE Main 2023 · 1 FEB · SHIFT 1Easy

Electric Flux & Gauss's Law

Let σ\sigma be the uniform surface charge density of two infinite thin plane sheets shown in figure. Then the electric fields in three different regions EI,EIIE_{I}, E_{II} and EIIIE_{III} are:

Figure

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Answer: (c)

  1. Each sheet gives σ2ϵ0\dfrac{\sigma}{2\epsilon_0} directed away from it; take n^\hat{n} pointing from region I towards III.
  2. Region I: both fields point left, E⃗I=−σϵ0n^\vec{E}_I = -\dfrac{\sigma}{\epsilon_0}\hat{n}.
  3. Region II: fields are opposite and cancel, E⃗II=0\vec{E}_{II} = 0.
  4. Region III: both point right, E⃗III=σϵ0n^\vec{E}_{III} = \dfrac{\sigma}{\epsilon_0}\hat{n}.
  5. So the answer is (c).
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