Let Ec and Ep represents kinetic energy of electron and photon… | MHT CET 2025 (26 Apr, Shift 2)

Q43MHT CET 2025 · 26 APR · SHIFT 2Difficult

Matter Waves: de Broglie Wavelength

Let $E_c$ and $E_p$ represents kinetic energy of electron and photon respectively. If de-Broglie wavelength of a photon is twice the de-Broglie wavelength of an electron then $E_p/E_c$ is (speed of electron $= C/100$ where C is the velocity of light)

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Answer: (b)

Electron: $p_e = m\dfrac{c}{100}$ , $\lambda_e = \dfrac{100h}{mc}$ , $E_c = \dfrac12 m\left(\dfrac{c}{100}\right)^2 = \dfrac{mc^2}{2\times10^4}$ .
Photon: $\lambda_p = 2\lambda_e = \dfrac{200h}{mc}$ , $E_p = \dfrac{hc}{\lambda_p} = \dfrac{mc^2}{200}$ .
$\dfrac{E_p}{E_c} = \dfrac{2\times10^4}{200} = 100$
So the answer is (b) $10^2$ .

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Matter Waves: de Broglie Wavelength question from MHT CET 2025 (26 Apr, Shift 2)

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