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MHT CET 2025 (26 Apr, Shift 1) · Excess Pressure: Drops & Bubbles

Excess Pressure: Drops & Bubbles question from MHT CET 2025 (26 Apr, Shift 1)

Q15MHT CET 2025 · 26 APR · SHIFT 1Easy

Excess Pressure: Drops & Bubbles

Let $R_1, R_2$ and $R_3$ be the radii of three mercury drops. A big mercury drop is formed from them under isothermal conditions. The radius of the resultant drop is

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Answer: (a)

Volume is conserved: $\frac{4}{3}\pi R^3 = \frac{4}{3}\pi(R_1^3 + R_2^3 + R_3^3)$ .
$R = \left(R_1^3 + R_2^3 + R_3^3\right)^{1/3}$
So the answer is (a).

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