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NEET 2024 · Self-Inductance & Energy

Self-Inductance & Energy question from NEET 2024

Q50NEET 2024Medium

Self-Inductance & Energy

Let us consider two solenoids $A$ and $B$ , made from same magnetic material of relative permeability $\mu_r$ and equal area of cross-section. Length of $A$ is twice that of $B$ and the number of turns per unit length in $A$ is half that of $B$ . The ratio of self inductances of the two solenoids, $L_A : L_B$ is

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Answer: (a)

$L = \mu_r \mu_0 n^2 A l$ ; same $\mu_r$ and $A$ , so $L \propto n^2 l$ .
$\dfrac{L_A}{L_B} = \left(\dfrac{1}{2}\right)^2 \times 2 = \dfrac{1}{2}$
So the answer is (a) $1 : 2$ .

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