Light of wavelength 5000 Å falls on a sensitive plate with photoelectric work function of 1.9 eV. The kinetic energy of the photoelectron emitted will be (a) 0.58 eV (b) 2.48 eV (c) 1.24 eV (d) 1.16 eV

Answer: (a). E = 12400λ(A) eV = (12400)/(5000) = 2.48 eV Kmax = E - φ = 2.48 - 1.9 = 0.58 eV So the answer is (a) 0.58 eV.

Light of wavelength 5000 Å falls on a sensitive plate with… | NEET 1998 (AIPMT)

Q170NEET 1998 · AIPMTEasy

Photoelectric Effect: Einstein's Equation

Light of wavelength $5000$ Å falls on a sensitive plate with photoelectric work function of $1.9\text{ eV}$ . The kinetic energy of the photoelectron emitted will be

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Answer: (a)

$E = \frac{12400}{\lambda(\mathring{A})}\text{ eV} = \frac{12400}{5000} = 2.48\text{ eV}$
$K_{max} = E - \phi = 2.48 - 1.9 = 0.58\text{ eV}$
So the answer is (a) $0.58\text{ eV}$ .

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