Physics Circle home Student Login

Home›Chapters›Wave Optics PYQs›Diffraction at a Single Slit›Question 70

MHT CET 2019 (2 May, Shift 2) · Diffraction at a Single Slit

Diffraction at a Single Slit question from MHT CET 2019 (2 May, Shift 2)

Q70MHT CET 2019 · 2 MAY · SHIFT 2Medium

Diffraction at a Single Slit

Light of wavelength ' λ\lambda ' is incident on a single slit of width ' aa ' and the distance between slit and screen is ' DD '. In diffraction pattern, if slit width is equal to the width of the central maximum then ' DD ' is equal to

Show answer and solution

Answer: (b)

  1. Linear width of central maximum =2λDa= \dfrac{2\lambda D}{a}
  2. Set equal to slit width: 2λDa=a\dfrac{2\lambda D}{a} = a
  3. So the answer is (b) D=a22λD = \dfrac{a^2}{2\lambda}.
Report a mistake

More questions on Diffraction at a Single Slit