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MHT CET 2021 (20 Sep, Shift 1) · Diffraction at a Single Slit

Diffraction at a Single Slit question from MHT CET 2021 (20 Sep, Shift 1)

Q62MHT CET 2021 · 20 SEP · SHIFT 1Medium

Diffraction at a Single Slit

Light of wavelength ' $\lambda$ ' is incident on a single slit of width 'a' and the distance between slit and screen is 'D'. In diffraction pattern, if slit width is equal to the width of the central maximum then $D =$

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Answer: (c)

Linear width of central maximum $= \dfrac{2\lambda D}{a}$
Set equal to slit width: $\dfrac{2\lambda D}{a} = a$
So the answer is (c) $D = \dfrac{a^2}{2\lambda}$ .

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