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MHT CET 2026 (15 Apr, Shift 1) · Diffraction at a Single Slit

Diffraction at a Single Slit question from MHT CET 2026 (15 Apr, Shift 1)

Q9MHT CET 2026 · 15 APR · SHIFT 1Medium

Diffraction at a Single Slit

Light of wavelength $\lambda$ is incident on a single slit of width 'a' and the distance between slit and screen is D. In diffraction pattern, if slit width is equal to the width of the central maximum then D is equal to

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Answer: (a)

Linear width of central maximum $= \dfrac{2\lambda D}{a}$
Set equal to slit width: $\dfrac{2\lambda D}{a} = a$
So the answer is (a) $D = \dfrac{a^2}{2\lambda}$ .

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