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MHT CET 2026 (15 Apr, Shift 2) · Diffraction at a Single Slit

Diffraction at a Single Slit question from MHT CET 2026 (15 Apr, Shift 2)

Q8MHT CET 2026 · 15 APR · SHIFT 2Medium

Diffraction at a Single Slit

Light of wavelength $\lambda$ is incident on a single slit of width 'a' and the distance between slit and screen is 'D'. In diffraction pattern, if slit width is equal to the width of the central maximum then 'D' is equal to

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Answer: (d)

Linear width of central maximum $= \dfrac{2\lambda D}{a}$
Set equal to slit width: $\dfrac{2\lambda D}{a} = a$
So the answer is (d) $D = \dfrac{a^2}{2\lambda}$ .

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