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MHT CET 2023 (9 May, Shift 2) · Diffraction at a Single Slit

Diffraction at a Single Slit question from MHT CET 2023 (9 May, Shift 2)

Q46MHT CET 2023 · 9 MAY · SHIFT 2Easy

Diffraction at a Single Slit

Light of wavelength ', $\lambda$ ' is incident on a slit of width ' $d$ '. The resulting diffraction pattern is observed on a screen at a distance ' $D$ '. The linear width of the principal maximum is then equal to the width of the slit if $D$ equals

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Answer: (b)

Linear width of central (principal) maximum $= \dfrac{2D\lambda}{d}$ .
Set it equal to the slit width: $\dfrac{2D\lambda}{d} = d$ .
So $D = \dfrac{d^2}{2\lambda}$ , answer (b).

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