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NEET 2020 (Phase 1) · Photons: Energy, Momentum & Radiation Pressure

Photons: Energy, Momentum & Radiation Pressure question from NEET 2020 (Phase 1)

Q29NEET 2020 · PHASE 1Medium

Photons: Energy, Momentum & Radiation Pressure

Light with an average flux of 20 W/cm2 falls on a non-reflecting surface at normal incidence having surface area 20 cm2. The energy received by the surface during time span of 1 minute is:

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Answer: (b)

  1. Energy E=(flux)×A×tE = (\text{flux})\times A\times t
  2. E=20 W/cm2×20 cm2×60 s=24000 JE = 20\text{ W/cm}^2\times 20\text{ cm}^2\times 60\text{ s} = 24000\text{ J}
  3. So the answer is (b) 24×103 J24\times10^{3}\text{ J}.
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