Lorentz magnetic force is acting on a particle of charge q moving with velocity V in magnetic field B. The work done by this force on the charged particle is (a) zero (b) V × B (c) V × V (d) q(V × B)

Answer: (a). F = q(V × B) is always perpendicular to V. Power F · V = 0, so work done is zero. So the answer is (a) zero.

Lorentz magnetic force is acting on a particle of charge q moving… | MHT CET 2026 (15 Apr, Shift 1)

Q2MHT CET 2026 · 15 APR · SHIFT 1Easy

Moving Charge in a Magnetic Field

Lorentz magnetic force is acting on a particle of charge $q$ moving with velocity $\vec{V}$ in magnetic field $\vec{B}$ . The work done by this force on the charged particle is

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Answer: (a)

$\vec{F} = q(\vec{V} \times \vec{B})$ is always perpendicular to $\vec{V}$ .
Power $\vec{F} \cdot \vec{V} = 0$ , so work done is zero.
So the answer is (a) zero.

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