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MHT CET 2024 (11 May, Shift 2) · Current Loop as a Magnetic Dipole

Current Loop as a Magnetic Dipole question from MHT CET 2024 (11 May, Shift 2)

Q31MHT CET 2024 · 11 MAY · SHIFT 2Medium

Current Loop as a Magnetic Dipole

Magnetic field at the centre of a circular loop of area ' AA ' is ' BB '. The magnetic moment of the loop will be

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Answer: (d)

  1. I=2Brμ0I = \frac{2Br}{\mu_0} and r=A/πr = \sqrt{A/\pi}.
  2. M=IA=2BAμ0⋅A1/2π1/2M = IA = \frac{2BA}{\mu_0}\cdot\frac{A^{1/2}}{\pi^{1/2}}
  3. So the answer is (d) 2BA3/2μ0π1/2\frac{2BA^{3/2}}{\mu_0\pi^{1/2}}.
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