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NEET 1999 (AIPMT) · Biot-Savart Law & Circular Coils

Biot-Savart Law & Circular Coils question from NEET 1999 (AIPMT)

Q111NEET 1999 · AIPMTEasy

Biot-Savart Law & Circular Coils

Magnetic field due to 0.1 A0.1\text{ A} current flowing through a circular coil of radius 0.1 m0.1\text{ m} and 1000 turns at the centre of the coil is

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Answer: (c)

  1. B=μ0nI2rB = \frac{\mu_0 n I}{2r}
  2. B=4π×10−7×1000×0.12×0.1=2π×10−4B = \frac{4\pi\times10^{-7}\times 1000\times 0.1}{2\times 0.1} = 2\pi\times10^{-4}
  3. So the answer is (c) 6.28×10−4 T6.28\times10^{-4}\text{ T}.
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