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JEE Main 2017 (8 Apr, Shift 1) · Nature of EM Waves & Wave Equation

Nature of EM Waves & Wave Equation question from JEE Main 2017 (8 Apr, Shift 1)

Q75JEE Main 2017 · 8 APR · SHIFT 1Medium

Nature of EM Waves & Wave Equation

Magnetic field in a plane electromagnetic wave is given by

B⃗\vec{B} = B0 sin (k x + ω\omegat) j^ T\hat{j}\,\text{T}

Expression for corresponding electric field will be:

Where c is speed of light.

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Answer: (a)

  1. (kx+ωt)(kx + \omega t): wave along −x-x; E0=cB0E_0 = cB_0.
  2. Need E^×j^=−i^\hat E\times\hat j = -\hat i: k^×j^=−i^\hat k\times\hat j = -\hat i, so E⃗\vec E along +k^+\hat k.
  3. So the answer is (a) E⃗=B0csin⁡(kx+ωt)k^\vec E = B_0c\sin(kx + \omega t)\hat k V/m.
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