Magnetic flux linked with the coil in weber is given by the equation Φ = 5t² + 6t + 11. The e.m.f. induced in the coil in the 5 th second will be (a) 10 V (b) 51 V (c) 102 V (d) 166 V

Answer: (b). "In the 5th second" means the interval t = 4 s to t = 5 s, so use average emf e = (ΔΦ)/(Δ t). Φ(5) = 125 + 30 + 11 = 166 Wb, Φ(4) = 80 + 24 + 11 = 115 Wb e = (166 - 115)/(1) = 51 V So the answer is (b) 51 V.

Magnetic flux linked with the coil in weber is given by the equation… | MHT CET 2026 (19 Apr, Shift 1)

Q6MHT CET 2026 · 19 APR · SHIFT 1Easy

Magnetic Flux & Faraday's Law

Magnetic flux linked with the coil in weber is given by the equation $\Phi = 5t^{2} + 6t + 11$ . The e.m.f. induced in the coil in the $5$ th second will be

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Answer: (b)

"In the 5th second" means the interval $t = 4$ s to $t = 5$ s, so use average emf $e = \frac{\Delta\Phi}{\Delta t}$ .
$\Phi(5) = 125 + 30 + 11 = 166$ Wb, $\Phi(4) = 80 + 24 + 11 = 115$ Wb
$e = \frac{166 - 115}{1} = 51$ V
So the answer is (b) $51$ V.

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