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MHT CET 2024 (15 May, Shift 1) · Current Loop as a Magnetic Dipole

Current Loop as a Magnetic Dipole question from MHT CET 2024 (15 May, Shift 1)

Q30MHT CET 2024 · 15 MAY · SHIFT 1Medium

Current Loop as a Magnetic Dipole

Magnetic induction produced at the centre of a circular loop of radius ' $R$ ' carrying a current is ' B '. The magnetic moment of the loop is ( $\mu_0 =$ permeability of free space)

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Answer: (b)

$B = \frac{\mu_0 I}{2R} \Rightarrow I = \frac{2BR}{\mu_0}$ .
$M = I\pi R^2 = \frac{2BR}{\mu_0}\pi R^2$
So the answer is (b) $\frac{2\pi BR^3}{\mu_0}$ .

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