Match List - I with List - II Choose the correct answer from the options given below List - I List - II (a) ω L > (1)/(ω C) (i) Current is in phase with emf (b) ω L = (1)/(ω C) (ii) Current lags behind the applied emf (c) ω L < (1)/(ω C) (iii) Maximum current occurs (d) Resonant frequency (iv) Current leads the emf (a) a(ii), b(i), c(iv), d(iii) (b) a(ii), b(i), c(iii), d(iv) (c) a(iii), b(i), c(iv), d(ii) (d) a(iv), b(iii), c(ii), d(i)

Answer: (a). ω L > (1)/(ω C): inductive circuit, current lags emf: (a)-(ii). ω L = (1)/(ω C): resonance, current in phase with emf: (b)-(i). ω L < (1)/(ω C): capacitive circuit, current leads emf: (c)-(iv). At resonant frequency Z = R is minimum, so current is maximum: (d)-(iii). So the answer is (a) a(ii), b(i), c(iv), d(iii).

Match List - I with List - II Choose the correct answer from the… | JEE Main 2021 (22 Jul, Shift 2)

Q96JEE Main 2021 · 22 JUL · SHIFT 2Medium

Resonance, Bandwidth & Q Factor

Match List - I with List - II

Choose the correct answer from the options given below

	List - I		List - II
(a)	$\omega L > \frac{1}{\omega C}$	(i)	Current is in phase with emf
(b)	$\omega L = \frac{1}{\omega C}$	(ii)	Current lags behind the applied emf
(c)	$\omega L < \frac{1}{\omega C}$	(iii)	Maximum current occurs
(d)	Resonant frequency	(iv)	Current leads the emf

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Answer: (a)

$\omega L > \frac{1}{\omega C}$ : inductive circuit, current lags emf: (a)-(ii).
$\omega L = \frac{1}{\omega C}$ : resonance, current in phase with emf: (b)-(i).
$\omega L < \frac{1}{\omega C}$ : capacitive circuit, current leads emf: (c)-(iv).
At resonant frequency $Z = R$ is minimum, so current is maximum: (d)-(iii).
So the answer is (a) a(ii), b(i), c(iv), d(iii).

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Resonance, Bandwidth & Q Factor question from JEE Main 2021 (22 Jul, Shift 2)

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