Match List I with List II: Choose the correct answer from the options given below: List I List II A. Intrinsic semiconductor I. Fermi-level near the valence band B. n-type semiconductor II. Fermi-level in the middle of valence and conduction band. C. p-type semiconductor III. Fermi-level near the conduction band D. Metals IV. Fermi-level inside the conduction band (a) A-III, B-I, C-II, D-IV (b) A-II, B-I, C-III, D-IV (c) A-I, B-II, C-III, D-IV (d) A-II, B-III, C-I, D-IV

Answer: (d). Intrinsic: equal ne and nh, so EF is midway between the bands: A-II. n-type: excess electrons push EF near the conduction band: B-III. p-type: excess holes pull EF near the valence band: C-I. Metals: EF lies inside the conduction band: D-IV. So the answer is (d) A-II, B-III, C-I, D-IV.

Match List I with List II: Choose the correct answer from the options… | JEE Main 2023 (1 Feb, Shift 1)

Q31JEE Main 2023 · 1 FEB · SHIFT 1Medium

Intrinsic & Extrinsic Semiconductors

Match List I with List II:

Choose the correct answer from the options given below:

	List I		List II
A.	Intrinsic semiconductor	I.	Fermi-level near the valence band
B.	n-type semiconductor	II.	Fermi-level in the middle of valence and conduction band.
C.	p-type semiconductor	III.	Fermi-level near the conduction band
D.	Metals	IV.	Fermi-level inside the conduction band

Show answer and solution

Answer: (d)

Intrinsic: equal $n_e$ and $n_h$ , so $E_F$ is midway between the bands: A-II.
n-type: excess electrons push $E_F$ near the conduction band: B-III.
p-type: excess holes pull $E_F$ near the valence band: C-I. Metals: $E_F$ lies inside the conduction band: D-IV.
So the answer is (d) A-II, B-III, C-I, D-IV.

Report a mistake

Intrinsic & Extrinsic Semiconductors question from JEE Main 2023 (1 Feb, Shift 1)

More questions on Intrinsic & Extrinsic Semiconductors