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JEE Main 2023 (25 Jan, Shift 2) · Units & Dimensions

Units & Dimensions question from JEE Main 2023 (25 Jan, Shift 2)

Q42JEE Main 2023 · 25 JAN · SHIFT 2Medium

Units & Dimensions

Match List I with List II

Figure

Choose the correct answer from the options given below:

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Answer: (d)

  1. Young's modulus = stress/strain =[ML−1T−2]= [\mathrm{ML^{-1}T^{-2}}] → III.
  2. Viscosity η=[ML−1T−1]\eta = [\mathrm{ML^{-1}T^{-1}}] → I.
  3. Planck's constant h=[ML2T−1]h = [\mathrm{ML^2T^{-1}}] → II.
  4. Work function is an energy =[ML2T−2]= [\mathrm{ML^2T^{-2}}] → IV.
  5. So the answer is (d) A-III, B-I, C-II, D-IV.
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