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JEE Main 2023 (29 Jan, Shift 1) · Applications of Dimensional Analysis

Applications of Dimensional Analysis question from JEE Main 2023 (29 Jan, Shift 1)

Q31JEE Main 2023 · 29 JAN · SHIFT 1Medium

Applications of Dimensional Analysis

Match List I with List II:

Choose the correct answer from the options given below:

List I (Physical Quantity)List II (Dimensional Formula)
A.Pressure gradientI.[M0L2T−2]\left[\mathrm{M^{0}L^{2}T^{-2}}\right]
B.Energy densityII.[M1L−1T−2]\left[\mathrm{M^{1}L^{-1}T^{-2}}\right]
C.Electric FieldIII.[M1L−2T−2]\left[\mathrm{M^{1}L^{-2}T^{-2}}\right]
D.Latent heatIV.[M1L1T−3A−1]\left[\mathrm{M^{1}L^{1}T^{-3}A^{-1}}\right]
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Answer: (a)

  1. Pressure gradient =P/L=ML−2T−2= P/L = ML^{-2}T^{-2} (A-III).
  2. Energy density == energy/volume =ML−1T−2= ML^{-1}T^{-2} (B-II).
  3. Electric field =F/q=MLT−3A−1= F/q = MLT^{-3}A^{-1} (C-IV).
  4. Latent heat == energy/mass =L2T−2= L^2T^{-2} (D-I).
  5. So the answer is (a) A-III, B-II, C-IV, D-I.
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