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JEE Main 2023 (8 Apr, Shift 2) · Units & Dimensions

Units & Dimensions question from JEE Main 2023 (8 Apr, Shift 2)

Q39JEE Main 2023 · 8 APR · SHIFT 2Medium

Units & Dimensions

Match List I with List II

Figure

Choose the correct answer from the options given below:

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Answer: (b)

  1. Torque =[ML2T−2]= [\mathrm{ML^2T^{-2}}] → II.
  2. Stress =F/A=[ML−1T−2]= F/A = [\mathrm{ML^{-1}T^{-2}}] → IV.
  3. Pressure gradient =dPdx=[ML−2T−2]= \dfrac{dP}{dx} = [\mathrm{ML^{-2}T^{-2}}] → I.
  4. Viscosity =[ML−1T−1]= [\mathrm{ML^{-1}T^{-1}}] → III.
  5. So the answer is (b) A-II, B-IV, C-I, D-III.
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