Match List I with List II Choose the correct answer from the options given below: List - I List - II (A) B · dl = μo ic + μo εo (dφE)/(dt) (I) Gauss' law for electricity (B) E · dl = (dφB)/(dt) (II) Gauss' law for magnetism (C) E · dA = (Q)/(εo) (III) Faraday law (D) B · dA = 0 (IV) Ampere - Maxwell law (a) A-IV, B-III, C-I, D-II (b) A-I, B-II, C-III, D-IV (c) A-IV, B-I, C-III, D-II (d) A-II, B-III, C-I, D-IV

Answer: (a). B· dl = μ₀ ic + μ₀ε₀(dφE)/(dt) is the Ampere-Maxwell law → A-IV. E· dl in terms of (dφB)/(dt) is Faraday's law → B-III. E· dA = Q/ε₀ is Gauss's law for electricity → C-I; B· dA = 0 is Gauss's law for magnetism → D-II. So the answer is (a) A-IV, B-III, C-I, D-II.

Match List I with List II Choose the correct answer from the options… | JEE Main 2024 (29 Jan, Shift 1)

Q13JEE Main 2024 · 29 JAN · SHIFT 1Easy

Lenz's Law, Eddy Currents & Induced Electric Field

Match List I with List II

Choose the correct answer from the options given below:

	List - I		List - II
(A)	$\oint \vec{B} \cdot \vec{dl} = \mu_o i_c + \mu_o \varepsilon_o \frac{d\phi_E}{dt}$	(I)	Gauss' law for electricity
(B)	$\oint \vec{E} \cdot \vec{dl} = \frac{d\phi_B}{dt}$	(II)	Gauss' law for magnetism
(C)	$\oint \vec{E} \cdot d\vec{A} = \frac{Q}{\varepsilon_o}$	(III)	Faraday law
(D)	$\oint \vec{B} \cdot d\vec{A} = 0$	(IV)	Ampere - Maxwell law

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Answer: (a)

$\oint \vec{B}\cdot d\vec{l} = \mu_0 i_c + \mu_0\varepsilon_0\dfrac{d\phi_E}{dt}$ is the Ampere-Maxwell law → A-IV.
$\oint \vec{E}\cdot d\vec{l}$ in terms of $\dfrac{d\phi_B}{dt}$ is Faraday's law → B-III.
$\oint \vec{E}\cdot d\vec{A} = Q/\varepsilon_0$ is Gauss's law for electricity → C-I; $\oint \vec{B}\cdot d\vec{A} = 0$ is Gauss's law for magnetism → D-II.
So the answer is (a) A-IV, B-III, C-I, D-II.

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Lenz's Law, Eddy Currents & Induced Electric Field question from JEE Main 2024 (29 Jan, Shift 1)

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