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JEE Main 2025 (2 Apr, Shift 1) · Units & Dimensions

Units & Dimensions question from JEE Main 2025 (2 Apr, Shift 1)

Q18JEE Main 2025 · 2 APR · SHIFT 1Easy

Units & Dimensions

Match List I with List II.

Figure

Choose the correct answer from the options given below:

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Answer: (c)

  1. Viscosity η=FA (dv/dx)=[ML−1T−1]\eta = \dfrac{F}{A\,(dv/dx)} = [\mathrm{ML^{-1}T^{-1}}] → (IV).
  2. Intensity =PA=[ML2T−3][L2]=[ML0T−3]= \dfrac{P}{A} = \dfrac{[\mathrm{ML^2T^{-3}}]}{[\mathrm{L^2}]} = [\mathrm{ML^0T^{-3}}] → (I).
  3. Pressure gradient =[ML−1T−2][L]=[ML−2T−2]= \dfrac{[\mathrm{ML^{-1}T^{-2}}]}{[\mathrm{L}]} = [\mathrm{ML^{-2}T^{-2}}] → (II).
  4. Compressibility =1/bulk modulus=[M−1LT2]= 1/\text{bulk modulus} = [\mathrm{M^{-1}LT^{2}}] → (III).
  5. So the answer is (c) A-IV, B-I, C-II, D-III.
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