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JEE Main 2025 (23 Jan, Shift 2) · Units & Dimensions

Units & Dimensions question from JEE Main 2025 (23 Jan, Shift 2)

Q21JEE Main 2025 · 23 JAN · SHIFT 2Easy

Units & Dimensions

Match List - I with List - II

Choose the correct answer from the options given below:

List - IList - II
(A)Permeability of free space(I)[ML2 T−2]\left[\mathrm{ML^{2}\ T^{-2}}\right]
(B)Magnetic field(II)[MT−2 A−1]\left[\mathrm{MT^{-2}\ A^{-1}}\right]
(C)Magnetic moment(III)[MLT−2 A−2]\left[\mathrm{MLT^{-2}\ A^{-2}}\right]
(D)Torsional constant(IV)[L2 A][\mathrm{L^{2}\ A}]
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Answer: (a)

  1. μ0\mu_0: from F/l=μ0I22πdF/l = \dfrac{\mu_0 I^2}{2\pi d}, [μ0]=[MLT−2A−2][\mu_0] = [\mathrm{MLT^{-2}A^{-2}}] → (III).
  2. B=Fqv=[MT−2A−1]B = \dfrac{F}{qv} = [\mathrm{MT^{-2}A^{-1}}] → (II).
  3. Magnetic moment =IA=[L2A]= IA = [\mathrm{L^2A}] → (IV).
  4. Torsional constant =τ/θ=[ML2T−2]= \tau/\theta = [\mathrm{ML^2T^{-2}}] → (I).
  5. So the answer is (a) A-III, B-II, C-IV, D-I.
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