Physics Circle home Student Login

Home›Chapters›Units, Dimensions and Measurement PYQs›Units & Dimensions›Question 20

JEE Main 2025 (28 Jan, Shift 2) · Units & Dimensions

Units & Dimensions question from JEE Main 2025 (28 Jan, Shift 2)

Q20JEE Main 2025 · 28 JAN · SHIFT 2Easy

Units & Dimensions

Match List - I with List - II.

Figure

Choose the correct answer from the options given below:

Show answer and solution

Answer: (c)

  1. Angular impulse =τ t= \tau\,t = change in angular momentum =[ML2T−1]= [\mathrm{ML^2T^{-1}}] → (III).
  2. Latent heat =Q/m=[M0L2T−2]= Q/m = [\mathrm{M^0L^2T^{-2}}] → (I).
  3. Resistivity ρ=RA/l=[ML2T−3A−2][L]=[ML3T−3A−2]\rho = RA/l = [\mathrm{ML^2T^{-3}A^{-2}}][\mathrm{L}] = [\mathrm{ML^3T^{-3}A^{-2}}] → (IV).
  4. EMF =W/q=[ML2T−3A−1]= W/q = [\mathrm{ML^2T^{-3}A^{-1}}] → (II).
  5. So the answer is (c) A-III, B-I, C-IV, D-II.
Report a mistake

More questions on Units & Dimensions